Answer by Piero D'Ancona for Plancherel-Polya Type Inequality for...
The following argument is particularly easy since $p\le1$, but it should not difficult to prove the same for all $p$, and the answer to your question is essentially negative.For a generic function $g$...
View ArticlePlancherel-Polya Type Inequality for non-compactly Fourier-supported Functions??
Hi!The Plancerel-Polya inequality can be stated as follows:Let $0 < p\le \infty$ and $ \nu \in \mathbb{Z}$. Suppose that $g$ is a (smooth) function satisfying $\mbox{supp }\hat g \subset \lbrace\xi:...
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